(navigation image)
Home American Libraries | Canadian Libraries | Universal Library | Community Texts | Project Gutenberg | Children's Library | Biodiversity Heritage Library | Additional Collections
Search: Advanced Search
Anonymous User (login or join us)
Upload
See other formats

Full text of "Treatise On Analysis Vol-Ii"

3    THE MODULUS FUNCTION ON A GROUP       257

a = 1 (because a > 0). This proves the first assertion. The second then follows
(13.14.3).

We deduce that if /is a locally /j-integrable function, then
(14.3.4.2)                           (/•AO~=(A-1/)-M.

(14.3.5)   In particular, if G is unimodular> then for each ju-integrable function
the functions yC?)/, §(s)f and / are /i-integrable, and we have

.3.5.1)    f f(sx) dtfd = (

(14.3

In particular, if A is any /i-integrable set in G, then

(14.3.5.2)

for all s e G.

When G is infinite and compact (resp. infinite and discrete) and therefore
unimodular (14.3.3), the normalized Haar measure on G is the unique Haar
measure \JL on G for which n(G) = 1 (resp. n({e}) = 1).

(14.3.6) Now let u be an automorphism of the topological group G. It is clear
that the image U~"I(IJL) of a left Haar measure \JL on G (13.1.6) is another left
Haar measure; hence (14.1.5) there exists a number a > 0, independent of the
choice of ju, such that U~I(IJL) = aju. This number a is called the modulus of the
automorphism uy and is denoted by modG(w) or mod(w). For every ^-integrable
function/we have therefore

f         t                               f

(14.3.6.1)               f(u~ \x)) d^(x) = (mod u) | /(x

and in particular, for any /i-integrable set A,

(14.3.6.2)                            Mw(A)) = (mod u

In particular, for each s e G, let is be the inner automorphism
Then we have /71 = &(S)Y(S\ an^ therefore

which proves that

(14.3J)                                  mod(fs) =1 • /i) = (50A-1) • (8(^) = (A^^A-1) • (A^)^) = A"1 - u,